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- From: Radu Mereuta <headness13 AT gmail.com>
- To: samira kherfellah <samira.kherfellah AT gmail.com>
- Cc: "k-user AT cs.uiuc.edu" <k-user AT cs.uiuc.edu>
- Subject: Re: [K-user] K variables
- Date: Wed, 3 Jul 2013 15:21:23 +0300
- List-archive: <http://lists.cs.uiuc.edu/pipermail/k-user/>
- List-id: <k-user.cs.uiuc.edu>
Hi Samira,
Did you put strict(2) as an attribute to the assignment syntax declaration?
Something else that I've noticed is the task rule. Variable I should be of type Int. That way the rule will apply only after the _expression_ on the right hand side of assignment will be evaluated.
Radu
K-developer
On Wed, Jul 3, 2013 at 1:46 PM, samira kherfellah <samira.kherfellah AT gmail.com> wrote:
Samira.and not<store> x |-> x + 1 </store><tenv> x |-> integer </tenv>But at execution, I have the result:To do this in k, I add the rules:task x := x + 1 ;var x integer ;in my program, we can use variables like this:Hi All,
.
.
.
Variables are initialized to 0.
rule <k> var X:Id TV:TypeVar ; => . ...</k>
<tenv>... . => X |-> TV ...</tenv>
<store>... . => X |-> 0 ...</store>
//task
rule <k> task X:Id := I:Exp ; => . ...</k>
<store>... X |-> (_=> I) ...</store>
<tenv>... X |-> integer ...</tenv>
//_expression_
rule I1:Int + I2:Int => I1 +Int I2
<tenv> x |-> integer </tenv>
<store> x |-> 1 </store>
I want to display the result of the _expression_ "x + 1" and not the _expression_ "x + 1"
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- [K-user] K variables, samira kherfellah, 07/03/2013
- Re: [K-user] K variables, Radu Mereuta, 07/03/2013
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